IIT-JEE 2011 · Paper 2 · Chemistry Q15

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ChemistryInteger+4Question 15 of 60

In 1 L saturated solution of AgCl [ $K_{sp}$ (AgCl) $=1.6\times10^{-10}$ ], 0.1 mol of CuCl [ $K_{sp}$ (CuCl) $=1.0\times10^{-6}$ ] is added. The resultant concentration of $\ce{Ag+}$ in the solution is $1.6\times10^{-x}$ . The value of " $x$ " is

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Answer and worked solution

Official answer: 7

Chloride from CuCl. CuCl is far more soluble, so it sets $[\ce{Cl-}]=\sqrt{1.0\times10^{-6}}=10^{-3}$ M. The AgCl contribution is negligible.

Silver. $[\ce{Ag+}]=\dfrac{1.6\times10^{-10}}{10^{-3}}=1.6\times10^{-7}$ M, so $x=7$ .

Answer: 7

Topics:Solubility product Common ion effect

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IIT-JEE 2011 · Paper 2, Chemistry question 15