IIT-JEE 2011 · Paper 2 · Chemistry Q14

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ChemistryInteger+4Question 14 of 60

The volume (in mL) of 0.1 M $\ce{AgNO3}$ required for complete precipitation of chloride ions present in 30 mL of 0.01 M solution of $\ce{[Cr(H2O)5Cl]Cl2}$ , as silver chloride is close to

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Answer and worked solution

Official answer: 6

Ionisable chloride. In $\ce{[Cr(H2O)5Cl]Cl2}$ only the two outer-sphere $\ce{Cl-}$ precipitate.

Moles. $30\times0.01=0.3$ mmol complex, so 0.6 mmol $\ce{Cl-}$ , needing 0.6 mmol $\ce{Ag+}$ : $V=\dfrac{0.6}{0.1}=6$ mL.

Answer: 6

Topics:Nomenclature Stoichiometry

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IIT-JEE 2011 · Paper 2, Chemistry question 14