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← IIT-JEE 2011 · Paper 2
ChemistryInteger+4Question 13 of 60

IIT-JEE 2011 · Paper 2, Chemistry question 13

Among the following, the number of compounds than can react with PClX5\ce{PCl5} to give POClX3\ce{POCl3} is

OX2\ce{O2}, COX2\ce{CO2}, SOX2\ce{SO2}, HX2O\ce{H2O}, HX2SOX4\ce{H2SO4}, PX4OX10\ce{P4O10}

Answer and worked solution

Official answer: 4

Reactions giving POClX3\ce{POCl3}:

  • PClX5+HX2O→POClX3+2 HCl\ce{PCl5 + H2O -> POCl3 + 2HCl}
  • PClX5+SOX2→POClX3+SOClX2\ce{PCl5 + SO2 -> POCl3 + SOCl2}
  • 2 PClX5+HX2SOX4→SOX2ClX2+2 POClX3+2 HCl\ce{2PCl5 + H2SO4 -> SO2Cl2 + 2POCl3 + 2HCl}
  • 6 PClX5+PX4OX10→10 POClX3\ce{6PCl5 + P4O10 -> 10POCl3}

OX2\ce{O2} does not react, and COX2\ce{CO2} is not counted (it does not react under ordinary conditions).

Answer: 4

Topics:Group 15