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← JEE Main 2026 · 8 Apr · Shift 2
ChemistryInteger+4 / -1Question 73 of 75

JEE Main 2026 · 8 Apr · Shift 2, Chemistry question 73

Consider two radiations of wavelengths

  1. λ1=2000\lambda_1=2000 Å

  2. λ2=6000\lambda_2=6000 Å

The ratio of the energies of these two radiations (E1E2)\left(\dfrac{E_1}{E_2}\right) is ________ (Nearest integer).

Answer and worked solution

Official answer: 3

Energy ∝1λ\propto\dfrac1\lambda: E1E2=60002000=3\dfrac{E_1}{E_2}=\dfrac{6000}{2000}=3.

Answer: 3