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← JEE Main 2026 · 8 Apr · Shift 2
ChemistryInteger+4 / -1Question 71 of 75

JEE Main 2026 · 8 Apr · Shift 2, Chemistry question 71

Number of paramagnetic complexes among the following is ________.

[MnBrX4]X2−\ce{[MnBr4]^2-}, [NiClX4]X2−\ce{[NiCl4]^2-}, [Ni(CN)X4]X2−\ce{[Ni(CN)4]^2-}, [Ni(CO)X4]\ce{[Ni(CO)4]}, [CoFX6]X3−\ce{[CoF6]^3-}, [Fe(CN)X6]X4−\ce{[Fe(CN)6]^4-}, [Mn(CN)X6]X3−\ce{[Mn(CN)6]^3-}, [Ti(CN)X6]X3−\ce{[Ti(CN)6]^3-}, [Cu(HX2O)X6]X2+\ce{[Cu(H2O)6]^2+}, [Co(CX2OX4)X3]X3−\ce{[Co(C2O4)3]^3-}

Answer and worked solution

Official answer: 6

Paramagnetic (unpaired electrons):

  • [MnBrX4]X2−\ce{[MnBr4]^2-} (d5d^5).
  • [NiClX4]X2−\ce{[NiCl4]^2-} (tetrahedral d8d^8).
  • [CoFX6]X3−\ce{[CoF6]^3-} (high-spin d6d^6).
  • [Mn(CN)X6]X3−\ce{[Mn(CN)6]^3-} (low-spin d4d^4, 2 unpaired).
  • [Ti(CN)X6]X3−\ce{[Ti(CN)6]^3-} (d1d^1).
  • [Cu(HX2O)X6]X2+\ce{[Cu(H2O)6]^2+} (d9d^9).

Diamagnetic: [Ni(CN)X4]X2−\ce{[Ni(CN)4]^2-}, [Ni(CO)X4]\ce{[Ni(CO)4]}, [Fe(CN)X6]X4−\ce{[Fe(CN)6]^4-} and [Co(CX2OX4)X3]X3−\ce{[Co(C2O4)3]^3-} (low-spin d6d^6).

Count: 6.

Answer: 6