JEE Main 2026 · 6 Apr · Shift 2 · Chemistry Q72

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ChemistryInteger+4 / -1Question 72 of 75

An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with $\ce{Cl2}/h\nu$ , (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is ________.

Your answer

Answer and worked solution

Official answer: 4

Alkane. $\ce{C_nH_{2n+2}}$ needs $\dfrac{3n+1}2$ mol of $\ce{O2}$ . Setting this to 8 gives $n=5$ .

One monochloro product. All hydrogens must be equivalent: neopentane, $\ce{C(CH3)4}$ .

Primary carbons: 4.

Answer: 4

Topics:Alkanes Stoichiometry

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JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 72