JEE Main 2026 · 6 Apr · Shift 2 · Chemistry Q71

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ChemistryInteger+4 / -1Question 71 of 75

An excess of $\ce{AgNO3}$ is added to 100 mL of a 0.05 M solution of tetraaquadichloridochromium (III) chloride. The number of moles of AgCl precipitated will be ________ $\times10^{-3}$ . (Nearest integer)

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Answer and worked solution

Official answer: 5

Ionisable chloride. $\ce{[Cr(H2O)4Cl2]Cl}$ has one $\ce{Cl-}$ outside the coordination sphere.

Moles. $0.1\times0.05=5\times10^{-3}$ mol of AgCl.

Answer: 5

Topics:Nomenclature

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JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 71