JEE Main 2026 · 6 Apr · Shift 2 · Chemistry Q56

← JEE Main 2026 · 6 Apr · Shift 2

ChemistrySingle correct+4 / -1Question 56 of 75

Given is a concentrated solution of a weak electrolyte $A_xB_y$ of concentration ' $c$ ' and dissociation constant ' $K$ '. The degree of dissociation is given by :

\left[K\times c^{x+y-1}x^xy^y\right]^{x+y}

\left(\dfrac K{c^{x+y-1}x^xy^y}\right)^{\frac1{x+y}}

\left(\dfrac{c^{x+y-1}x^xy^y}K\right)^{x+y}

\left(\dfrac{c^{x+y-1}x^xy^y}K\right)^{\frac1{x+y}}

Answer and worked solution

Official answer: B

Equilibrium. $\ce{A_xB_y <=> xA + yB}$ :
$K=\frac{(xc\alpha)^x(yc\alpha)^y}{c(1-\alpha)}\approx x^xy^yc^{x+y-1}\alpha^{x+y}$
for small α.

So
$\alpha=\left(\frac K{c^{x+y-1}x^xy^y}\right)^{\frac1{x+y}}.$

(B)

Topics:pH and ionisation

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JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 56