Skip to content
dronacharya.ai
← JEE Main 2026 · 6 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 33 of 75

JEE Main 2026 · 6 Apr · Shift 1, Physics question 33

The position of center of mass of three masses 2 kg, 3 kg and 15 kg placed with respect to mid point (pp) of normal bisector, as shown in the figure is ________.

An isosceles triangle: 15 kg at the apex, joined by 10 m rods at 120° to 2 kg at the lower left and 3 kg at the lower right; a dashed perpendicular from the apex to the base has its midpoint marked p.
Choose one option
Answer and worked solution

Official answer: A

Coordinates. The base half-width is 10sin⁡60∘=5310\sin60^\circ=5\sqrt3 and the height is 10cos⁡60∘=510\cos60^\circ=5. Put the origin at p, the midpoint of the altitude:

  • 2 kg at (−53,−2.5)(-5\sqrt3,-2.5).
  • 3 kg at (53,−2.5)(5\sqrt3,-2.5).
  • 15 kg at (0,2.5)(0,2.5).

Centre of mass.
x=−103+15320=34,y=−5−7.5+37.520=1.25.x=\frac{-10\sqrt3+15\sqrt3}{20}=\frac{\sqrt3}4,\qquad y=\frac{-5-7.5+37.5}{20}=1.25.

(A)

Topics:Centre of mass
← Previous questionNext question →