JEE Main 2026 · 6 Apr · Shift 1 · Physics Q32

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PhysicsSingle correct+4 / -1Question 32 of 75

A smooth inclined plane ends in a vertical circular loop, as shown in the figure. A small body is released from height $h$ as shown. If the body exerts a force of three times its weight on the plane at the highest point of circle then the height $h=\alpha R$ . The value of $\alpha$ is ________.

A body at the top of a smooth incline of height h; the incline runs down to the right into a vertical circular loop of radius R.

Answer and worked solution

Official answer: B

Top of the loop. The normal force is 3mg, so
$\frac{mv^2}R=mg+3mg\ \Rightarrow\ v^2=4gR.$

Energy.
$gh=g(2R)+\tfrac12(4gR)\ \Rightarrow\ h=4R.$

(B)

Topics:Motion in a vertical circle

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JEE Main 2026 · 6 Apr · Shift 1, Physics question 32