JEE Main 2026 · 6 Apr · Shift 1 · Mathematics Q19

MathematicsSingle correct+4 / -1Question 19 of 75

The area of the region $\{(x,y):0\le y\le6-x,\ y^2\ge4x-3,\ x\ge0\}$ is:

Answer and worked solution

Official answer: B

Strips in y. x runs from 0 to $\min\left(\tfrac{y^2+3}4,\ 6-y\right)$ . The curves meet where $y^2+4y-21=0$ , at $y=3$ .

Area.
$\int_0^3\frac{y^2+3}4\,dy+\int_3^6(6-y)\,dy=\frac{18}4+\frac92=9.$

(B)

Topics:Area between curves Parabola

JEE Main 2026 · 6 Apr · Shift 1, Mathematics question 19