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← JEE Main 2026 · 6 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 59 of 75

JEE Main 2026 · 6 Apr · Shift 1, Chemistry question 59

Given below are two statements:

Statement I: Aluminium is more electropositive than thallium as the standard electrode potential value of EAlX3+/Al∘E^\circ_{\ce{Al^3+}/\ce{Al}} is negative and ETlX3+/Tl∘E^\circ_{\ce{Tl^3+}/\ce{Tl}} is positive.

Statement II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms AlX3+\ce{Al^3+} ion.

In the light of the above statements, choose the correct answer from the options given below

Choose one option
Answer and worked solution

Official answer: A

Statement I. E∘(AlX3+/Al)=−1.66E^\circ(\ce{Al^3+}/\ce{Al})=-1.66 V and E∘(TlX3+/Tl)=+1.26E^\circ(\ce{Tl^3+}/\ce{Tl})=+1.26 V. So Al is the more electropositive. True.

Statement II. Boron's very high sum of the first three ionisation enthalpies prevents BX3+\ce{B^3+} from forming, so boron forms only covalent compounds. Aluminium forms AlX3+\ce{Al^3+}. True.

(A)

Topics:Group 13