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← JEE Main 2026 · 5 Apr · Shift 2
PhysicsInteger+4 / -1Question 49 of 75

JEE Main 2026 · 5 Apr · Shift 2, Physics question 49

When an external resistance of 5 Ω is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5 Ω resistor is replaced by a 2 Ω resistor, a current of 0.5 A flows through it. The internal resistance of the cell is ________ Ω.

Answer and worked solution

Official answer: 1

Same EMF.
0.25(5+r)=0.5(2+r) ⇒ 1.25+0.25r=1+0.5r ⇒ r=1 Ω.0.25(5+r)=0.5(2+r)\ \Rightarrow\ 1.25+0.25r=1+0.5r\ \Rightarrow\ r=1\ \Omega.

Answer: 1