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← JEE Main 2026 · 5 Apr · Shift 2
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JEE Main 2026 · 5 Apr · Shift 2, Physics question 48

A series LCR circuit with R=20R=20 Ω, L=1.6L=1.6 H and C=40C=40 μF is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is ________ Ω.

Answer and worked solution

Official answer: 200

Resonance.
ω=1LC=11.6×40×10−6=125 rad/s.\omega=\frac1{\sqrt{LC}}=\frac1{\sqrt{1.6\times40\times10^{-6}}}=125\text{ rad/s}.

Reactance. XL=ωL=125×1.6=200X_L=\omega L=125\times1.6=200 Ω.

Answer: 200