JEE Main 2026 · 5 Apr · Shift 2 · Mathematics Q7 · Dronacharya Exams

My attemptsTake a paper

← JEE Main 2026 · 5 Apr · Shift 2

MathematicsSingle correct+4 / -1Question 7 of 75

The coefficient of $x^2$ in the expansion of $\left(2x^2+\dfrac1x\right)^{10}$ , $x\ne0$ , is :

A

3240

B

3360

C

3480

D

3600

Answer and worked solution

Official answer: B

General term. $\binom{10}r(2x^2)^{10-r}x^{-r}$ has exponent $20-3r=2$ , so $r=6$ .

Coefficient. $\binom{10}6\cdot2^4=210\cdot16=3360$ .

(B)

Topics:General and middle terms

← Previous question Next question →