JEE Main 2026 · 5 Apr · Shift 2 · Mathematics Q6

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MathematicsSingle correct+4 / -1Question 6 of 75

Let $A_1,A_2,A_3,\dots,A_{39}$ be 39 arithmetic means between the numbers 59 and 159. Then the mean of $A_{25},A_{28},A_{31}$ and $A_{36}$ is equal to :

129

136

131.50

134

Answer and worked solution

Official answer: D

Common difference. 39 means give 40 equal steps: $d=\dfrac{159-59}{40}=2.5$ , and $A_k=59+2.5k$ .

Mean. The mean of $k=25,28,31,36$ is 30, so the mean is $A_{30}=59+75=134$ .

(D)

Topics:Arithmetic progression

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JEE Main 2026 · 5 Apr · Shift 2, Mathematics question 6