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← JEE Main 2026 · 5 Apr · Shift 2
ChemistryInteger+4 / -1Question 72 of 75

JEE Main 2026 · 5 Apr · Shift 2, Chemistry question 72

RMgI when treated with ice cold water liberated a gas which occupied 1.4 dm³/g at STP. The gas produced is further reacted with iodine in presence of HIOX3\ce{HIO3} to give compound (X). Compound (X) in presence of Na and dry ether produced compound (Y). Molar mass of compound (Y) is ________ g mol−1^{-1}. (Nearest integer)

Answer and worked solution

Official answer: 30

The gas. 1 g occupies 1.4 dm³ at STP, so its molar mass is 22.41.4=16\tfrac{22.4}{1.4}=16 g mol−1^{-1}: methane. So RMgI is CHX3MgI\ce{CH3MgI}.

X. CHX4+IX2\ce{CH4 + I2} with HIOX3\ce{HIO3} (which removes HI) gives CHX3I\ce{CH3I}.

Y. The Wurtz reaction, 2 CHX3I+2 Na\ce{2CH3I + 2Na} in dry ether, gives ethane CX2HX6\ce{C2H6}, with M = 30.

Answer: 30