JEE Main 2026 · 5 Apr · Shift 2 · Chemistry Q66

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ChemistrySingle correct+4 / -1Question 66 of 75

Given below are two statements :

Statement I: The condensation reaction between $\ce{CH3-CH=O}$ and $\ce{H2N-NH-C(=O)-NH2}$ under optimum pH will produce $\ce{CH3-CH=N-C(=O)-NH-NH2}$

Statement II: The molecule, $\ce{Ph-CH(OH)(OCH3)}$ will generate $\ce{Ph-CH=O}$ in the presence of dilute acid.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Answer and worked solution

Official answer: D

Statement I. Semicarbazide reacts through the terminal $\ce{-NH2}$ of its hydrazine part. The amide $\ce{NH2}$ is deactivated by the carbonyl. The product is the semicarbazone $\ce{CH3CH=N-NH-CO-NH2}$ , not $\ce{CH3CH=N-CO-NH-NH2}$ . False.

Statement II. $\ce{PhCH(OH)(OCH3)}$ is a hemiacetal. In dilute acid it loses methanol and gives benzaldehyde. True.

(D)

Topics:Nucleophilic addition

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JEE Main 2026 · 5 Apr · Shift 2, Chemistry question 66