JEE Main 2026 · 5 Apr · Shift 2 · Chemistry Q65 · Dronacharya Exams

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ChemistrySingle correct+4 / -1Question 65 of 75

Complete the following reaction sequence and give the name of major product 'P'.

Propanenitrile (drawn as a skeletal chain ending in C≡N) treated with (i) OH⁻/H₂O/Δ, (ii) H₃O⁺, (iii) Cl₂/red P, (iv) H₂O gives P (major product).

A

2-Chloropropanoic acid

B

3-Chloropropanoic acid

C

1-Chloropropane

D

2-Chloropropane

Answer and worked solution

Official answer: A

Step by step from propanenitrile, $\ce{CH3CH2CN}$ :

Alkaline hydrolysis, then acidification, gives propanoic acid, $\ce{CH3CH2COOH}$ .
$\ce{Cl2}$ /red P (Hell-Volhard-Zelinsky) chlorinates the α-carbon. Water then gives $\ce{CH3CHClCOOH}$ .

P: 2-chloropropanoic acid.

(A)

Topics:Carboxylic acids Cyanides and isocyanides

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