Skip to content
dronacharya.ai
← JEE Main 2026 · 5 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 29 of 75

JEE Main 2026 · 5 Apr · Shift 1, Physics question 29

Three masses m1=4m_1=4 kg, m2=4m_2=4 kg and m3=6m_3=6 kg are suspended from a fixed smooth frictionless pully as shown in the figure below. The value of T1/T2T_1/T_2 is ________.
(take g=10g=10 m/s²)

A pulley hung from the ceiling; a string over it carries m₁ on the left (tension T₁) and m₂ on the right (tension T₁); m₃ hangs below m₂ from a second string with tension T₂.
Choose one option
Answer and worked solution

Official answer: A

Acceleration. m1=4m_1=4 kg on one side, m2+m3=10m_2+m_3=10 kg on the other:
a=(10−4)g14=307 m/s2,a=\frac{(10-4)g}{14}=\frac{30}7\text{ m/s}^2,
with m1m_1 moving up.

Tensions.

  • T1=m1(g+a)=4⋅1007=4007T_1=m_1(g+a)=4\cdot\dfrac{100}7=\dfrac{400}7 N.
  • T2=m3(g−a)=6⋅407=2407T_2=m_3(g-a)=6\cdot\dfrac{40}7=\dfrac{240}7 N.

Ratio: T1/T2=5/3T_1/T_2=5/3.

(A)