JEE Main 2026 · 5 Apr · Shift 1 · Physics Q28

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PhysicsSingle correct+4 / -1Question 28 of 75

When one moves from a point 16 km below the earth's surface to a point 16 km above the earth's surface. The change in g is approximately $\alpha$ %. The value of $\alpha$ is ________.
(Take radius of the earth = 6400 km.)

0.12

0.25

0.50

0.75

Answer and worked solution

Official answer: B

Depth d. $g_d=g\left(1-\dfrac dR\right)$ .

Height h (with $h\ll R$ ). $g_h\approx g\left(1-\dfrac{2h}R\right)$ .

Change.
$\frac{g_h-g_d}g=\frac{d-2h}R=\frac{16-32}{6400}=-0.25\%,$
so g falls by about 0.25%.

(B)

Topics:Variation of g

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JEE Main 2026 · 5 Apr · Shift 1, Physics question 28