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← JEE Main 2026 · 5 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 65 of 75

JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 65

For the following Friedel Craft's alkylation reaction, which of the statements are correct?

A. Major product is n-propyl benzene.

B. iso-propyl carbocation intermediate is also generated.

C. Multiple substitution is inevitable.

D. Introducing electron-donating substituent on benzene will not produce any alkyl benzene.

Choose the correct answer from the options given below:

Benzene + 1-chloropropane (CH₃CH₂CH₂Cl) with anhydrous AlCl₃ gives alkylbenzene.
Choose one option
Answer and worked solution

Official answer: B

Each statement.

  • A: The primary propyl cation rearranges (hydride shift) to the isopropyl cation. The major product is isopropylbenzene (cumene), not n-propylbenzene. False.
  • B: The iso-propyl carbocation is generated. True.
  • C: The alkyl group activates the ring, so polyalkylation occurs. True.
  • D: Electron-donating groups activate the ring and still give alkylbenzenes. False.

Correct: B and C.

(B)