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← JEE Main 2026 · 5 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 56 of 75

JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 56

Arrange the following resultant mixtures in increasing order of their pH values

A. 10 mL 0.2 M Ca(OH)X2\ce{Ca(OH)2} + 25 mL 0.1 M HCl

B. 10 mL 0.01 M HX2SOX4\ce{H2SO4} + 10 mL 0.01 M Ca(OH)X2\ce{Ca(OH)2}

C. 10 mL 0.1 M HX2SOX4\ce{H2SO4} + 10 mL 0.1 M KOH

Choose the correct answer from the options given below:

Choose one option
Answer and worked solution

Official answer: C

Each mixture (in mmol).

  • A: OHX−=10×0.2×2=4\ce{OH-}=10\times0.2\times2=4 and HX+=2.5\ce{H+}=2.5, so 1.5 mmol OHX−\ce{OH-} is left: basic.
  • B: HX+=10×0.01×2=0.2\ce{H+}=10\times0.01\times2=0.2 and OHX−=0.2\ce{OH-}=0.2: neutral.
  • C: HX+=10×0.1×2=2\ce{H+}=10\times0.1\times2=2 and OHX−=1\ce{OH-}=1, so 1 mmol HX+\ce{H+} is left: acidic.

Increasing pH: C < B < A.

(C)