JEE Main 2026 · 5 Apr · Shift 1 · Chemistry Q52

ChemistrySingle correct+4 / -1Question 52 of 75

Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.

A. $n=3$ , $l=2$ , $m=+1$

B. $n=4$ , $l=0$ , $m=0$

C. $n=6$ , $l=1$ , $m=0$

D. $n=5$ , $l=1$ , $m=+1$

E. $n=2$ , $l=1$ , $m=+1$

Choose the correct answer from the options given below:

C < D < B < A < E

B < A < E < C < D

E < C < D < B < A

E < B < A < D < C

Answer and worked solution

Official answer: D

The (n + l) rule. Lower $n+l$ means lower energy; for equal $n+l$ , lower n comes first.

Orbital	E (2p)	B (4s)	A (3d)	D (5p)	C (6p)
$n+l$	3	4	5	6	7

Order: E < B < A < D < C.

(D)

Topics:Quantum numbers Electronic configuration

JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 52