JEE Main 2026 · 5 Apr · Shift 1 · Chemistry Q51

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ChemistrySingle correct+4 / -1Question 51 of 75

How many grams of residue is obtained by heating 2.76 g of silver carbonate?
(Given : Molar mass of C, O and Ag are 12, 16 and 108 g mol $^{-1}$ respectively)

1.08 g

2.16 g

3.24 g

4.32 g

Answer and worked solution

Official answer: B

Decomposition. On heating, silver carbonate leaves silver:
$\ce{Ag2CO3 -> 2Ag + CO2 + 1/2 O2}$

Amounts. $M(\ce{Ag2CO3})=276$ , so 2.76 g is 0.01 mol. That gives 0.02 mol Ag, or $0.02\times108=2.16$ g.

(B)

Topics:Stoichiometry

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JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 51