JEE Main 2026 · 4 Apr · Shift 2 · Physics Q37

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PhysicsSingle correct+4 / -1Question 37 of 75

From the circuit given below, the capacitance between terminals $A$ and $B$ shown in the circuit is ________ μF.
(take $C_1=C_2=C_3=1$ μF and $C_4=2$ μF.)

C₁, C₂ and C₃ in a row from A to B. A wire above joins A to the junction of C₂ and C₃ (bypassing C₁ and C₂ in series); C₄ below joins the junction of C₁ and C₂ to B.

7/2

7/3

5/2

Answer and worked solution

Official answer: A

Redraw. The top wire makes A and the C₂-C₃ junction the same node.

$C_3$ (1 μF) joins A directly to B.
$C_1$ and $C_2$ both join A to the C₁-C₂ junction N: in parallel, 2 μF.
N connects to B through $C_4$ (2 μF), so that path is 1 μF.

Total $1+1=2$ μF.

(A)

Topics:Series and parallel combinations

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JEE Main 2026 · 4 Apr · Shift 2, Physics question 37