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JEE Main 2026 · 4 Apr · Shift 2, Physics question 36

A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field E⃗1=E0x^\vec E_1=E_0\hat x. If another electric field E⃗2=2E0(y^+z^)\vec E_2=2E_0\left(\hat y+\hat z\right) is introduced to the system, what will be the percentage change in the frequency of the oscillation (approximate)?

Choose one option
Answer and worked solution

Official answer: A

Frequency of a dipole in a field. ω=pE/I∝E\omega=\sqrt{pE/I}\propto\sqrt E.

New field. E⃗1+E⃗2=E0(1,2,2)\vec E_1+\vec E_2=E_0(1,2,2), of magnitude 3E03E_0.

Change. The frequency rises by a factor 3=1.73\sqrt3=1.73, i.e. about 73%.

(A)

Topics:Electric dipoleSimple harmonic motion
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