20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X)?
( value of acetic acid is 4.75).
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JEE Main 2026 · 4 Apr · Shift 2, Chemistry question 55
Answer and worked solution
Official answer: B
Half-neutralised. Full neutralisation takes 28.4 mL, so 14.2 mL neutralises exactly half the acid: .
pH = p = 4.75.
(B)