JEE Main 2026 · 4 Apr · Shift 2 · Chemistry Q54

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ChemistrySingle correct+4 / -1Question 54 of 75

At 27 °C, 0.1 M, 1 L $\ce{K4[Fe(CN)6]}$ aqueous solution and 0.1 M, 1 L $\ce{FeCl3}$ aqueous solution are placed in a container separated by a semi permeable membrane AB. Assume complete dissociation of both the solutes. Which of the following statement is correct?

A container divided by a vertical semi-permeable membrane AB: side 'x' (left) holds 0.1 M, 1 L K₄[Fe(CN)₆] and side 'y' (right) holds 0.1 M, 1 L FeCl₃.

Blue color is formed on both sides.

Ionic solutes in aqueous solution can pass through semi-permeable membrane.

Solution on side 'y' is hypotonic.

To cause the reverse flow of solvent during osmosis, external pressure (any value) should be applied to side 'x'.

Answer and worked solution

Official answer: C

Effective concentrations (complete dissociation):

$\ce{K4[Fe(CN)6]}$ : $i=5$ , so 0.5 M particles (side x).
$\ce{FeCl3}$ : $i=4$ , so 0.4 M particles (side y).

Side y is more dilute, i.e. hypotonic.

Other options. The semipermeable membrane stops ions, so no Prussian blue forms (A) and (B) is false. Reversing osmosis needs pressure greater than the osmotic pressure, not "any value" (D).

(C)

Topics:Colligative properties van't Hoff factor

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JEE Main 2026 · 4 Apr · Shift 2, Chemistry question 54