JEE Main 2026 · 4 Apr · Shift 1 · Physics Q50

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An inductor of 10 mH, capacitor of 0.1 μF and a resistor of 100 Ω are connected in series across an $a.c$ power supply 220 V, 70 Hz. The power factor of the given circuit is 0.5. The difference in the inductive reactance and capacitance reactance is $\sqrt3\,\alpha$ Ω. The value of $\alpha$ is ________.

Your answer

Answer and worked solution

Official answer: 100

Power factor 0.5 means $\phi=60^\circ$ and $\tan\phi=\dfrac{X_L-X_C}R=\sqrt3$ .

Difference. $X_L-X_C=100\sqrt3$ Ω, so $\alpha=100$ . (The question fixes the power factor at 0.5; the listed L, C and f are not used.)

Answer: 100

Topics:LCR circuits and resonance Power in AC circuits

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JEE Main 2026 · 4 Apr · Shift 1, Physics question 50