JEE Main 2026 · 4 Apr · Shift 1 · Chemistry Q51

ChemistrySingle correct+4 / -1Question 51 of 75

Number of moles and number of molecules in 1.4187 L of $\ce{SO2}$ at STP respectively are

0.1266;

3.812\times10^{22}

0.0633;

3.812\times10^{22}

0.1266;

7.6238\times10^{22}

0.0633;

7.6238\times10^{22}

Answer and worked solution

Official answer: B

Moles at STP. $\frac{1.4187}{22.4}=0.0633$ mol.

Molecules. $0.0633\times6.022\times10^{23}=3.81\times10^{22}$ .

(B)

Topics:Mole concept

JEE Main 2026 · 4 Apr · Shift 1, Chemistry question 51