JEE Main 2026 · 4 Apr · Shift 1 · Physics Q32

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The graph shows variation of stopping potential $V_0$ with the frequency $\nu$ of the incident radiation for three photosensitive metals $X_1$ , $X_2$ and $X_3$ . Which metal will give out electrons with greater kinetic energy, for the same wavelength of incident radiation?

Stopping potential V₀ against frequency ν (×10¹⁴ Hz): three parallel straight lines for X₁, X₂, X₃ meeting the ν-axis at 1.0, 1.5 and 2, respectively.

X_1

X_2

X_3

All the metals will give out photo electrons with same kinetic energies.

Answer and worked solution

Official answer: A

Einstein's equation. $K_{\max}=h(\nu-\nu_0)$ . For the same ν, the metal with the lowest threshold frequency ( $X_1$ , $\nu_0=1.0\times10^{14}$ Hz) gives the most energetic electrons.

(A)

Topics:Photoelectric effect

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JEE Main 2026 · 4 Apr · Shift 1, Physics question 32