JEE Main 2026 · 4 Apr · Shift 1 · Physics Q31

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The two projectiles are projected with the same initial velocities at the 15° and 30° with respect to the horizontal. The ratio of their ranges is $1:x$ . The value of $x$ is

\sqrt2

\sqrt3

2\sqrt3

\dfrac1{\sqrt2}

Answer and worked solution

Official answer: B

Range $\propto\sin2\theta$ : $\sin30^\circ:\sin60^\circ=1:\sqrt3$ , so $x=\sqrt3$ .

(B)

Topics:Projectile motion

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JEE Main 2026 · 4 Apr · Shift 1, Physics question 31