JEE Main 2026 · 4 Apr · Shift 1 · Chemistry Q73

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ChemistryInteger+4 / -1Question 73 of 75

2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is ________.
(Given molar mass in g mol $^{-1}$ H:1, C:12, Br : 80, Ag : 108)

Your answer

Answer and worked solution

Official answer: 5

Bromine. $3.36\times\frac{80}{188}=1.43$ g in 2.0 g, i.e. 71.5%.

Composition. C 26.7% and H 1.8%.

Mole ratio. C : H : Br $=\frac{26.7}{12}:\frac{1.8}1:\frac{71.5}{80}=2.22:1.8:0.894=2.5:2:1$ , i.e. $\ce{C5H4Br2}$ .

5 carbons.

Answer: 5

Topics:Qualitative and quantitative analysis of organic compounds Empirical and molecular formula

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JEE Main 2026 · 4 Apr · Shift 1, Chemistry question 73