JEE Main 2026 · 4 Apr · Shift 1 · Chemistry Q67 · Dronacharya Exams

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ChemistrySingle correct+4 / -1Question 67 of 75

Product C of the following reaction sequence will be

Aniline → (Br₂/water) A (major product) → (NaNO₂/HCl, 273-278 K) B → ((i) HBF₄; (ii) NaNO₂, Cu, Δ) C.

A

1-Bromo-4-nitrobenzene

B

1, 3, 5-Tribromo-2-nitrobenzene

C

4-Bromo-1-nitrobenzene

D

1, 3, 5-Tribromobenzene

Answer and worked solution

Official answer: B

Sequence.

Bromine water gives 2,4,6-tribromoaniline (A).
Diazotisation gives the diazonium salt (B).
$\ce{HBF4}$ forms the fluoroborate, and $\ce{NaNO2}$ /Cu, Δ replaces $\ce{N2+}$ by $\ce{NO2}$ .

C = 2,4,6-tribromonitrobenzene, i.e. 1,3,5-tribromo-2-nitrobenzene.

(B)

Topics:Diazonium salts Amines

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