Two resistors of 200 Ω and 400 Ω are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected across the 400 Ω resistance. The potential drop across the bulb is ________ V.
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JEE Main 2026 · 2 Apr · Shift 2, Physics question 38
Answer and worked solution
Official answer: B
Bulb resistance. Ω.
Circuit. Bulb ∥ 400 Ω gives 200 Ω, in series with 200 Ω: the 100 V splits equally.
Drop across the bulb = 50 V.
(B)