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JEE Main 2026 · 2 Apr · Shift 2, Physics question 37

An electromagnetic wave travels in free space along the xx-direction. At a particular point in space and time, B⃗=2×10−7j^\vec B=2\times10^{-7}\hat j T is associated with this wave. The value of corresponding electric field E⃗\vec E at this point is ________ V/m.

Choose one option
Answer and worked solution

Official answer: B

Magnitude. E=cB=3×108×2×10−7=60E=cB=3\times10^8\times2\times10^{-7}=60 V/m.

Direction. E⃗×B⃗\vec E\times\vec B must point along +x^+\hat x. With B⃗\vec B along j^\hat j: (−k^)×j^=i^(-\hat k)\times\hat j=\hat i, so E⃗=−60k^\vec E=-60\hat k V/m.

(B)

Topics:Properties of EM waves
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