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JEE Main 2026 · 2 Apr · Shift 2, Physics question 35

If an air bubble of diameter 2 mm rises steadily through a liquid of density 2000 kg/m³ at a rate of 0.5 cm/s, then the coefficient of viscosity of liquid is ________ Poise. (Take g=10g=10 m/s²)

Choose one option
Answer and worked solution

Official answer: B

Terminal velocity (air's density negligible):
v=2r2ρg9η  ⟹  η=2(10−3)2(2000)(10)9(5×10−3)=0.889 Pa s.v=\frac{2r^2\rho g}{9\eta}\implies\eta=\frac{2(10^{-3})^2(2000)(10)}{9(5\times10^{-3})}=0.889\text{ Pa s}.

In poise. 0.8890.889 Pa s =8.89≈8.8=8.89\approx8.8 poise.

(B)

Topics:Terminal velocityViscosity and Stokes' law
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