Skip to content
dronacharya.ai
← JEE Main 2026 · 2 Apr · Shift 2
PhysicsSingle correct+4 / -1Question 34 of 75

JEE Main 2026 · 2 Apr · Shift 2, Physics question 34

A mixture of carbon dioxide and oxygen has volume 8310 cm³, temperature 300 K, pressure 100 kPa and mass 13.2 g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are ________.
(Assume both carbon dioxide and oxygen gases behave like ideal gases) [R=8.31R=8.31 J/mol.K]

Choose one option
Answer and worked solution

Official answer: C

Total moles. n=PVRT=105×8.31×10−38.31×300=13n=\dfrac{PV}{RT}=\dfrac{10^5\times8.31\times10^{-3}}{8.31\times300}=\dfrac13 mol.

Mass equation. 44a+32(13−a)=13.244a+32\left(\frac13-a\right)=13.2 gives a=0.21a=0.21 mol COX2\ce{CO2} and b=0.12b=0.12 mol OX2\ce{O2}.

(C)