JEE Main 2026 · 2 Apr · Shift 2 · Chemistry Q54

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ChemistrySingle correct+4 / -1Question 54 of 75

Gas 'A' undergoes change from state 'X' to state 'Y'. In this process, the heat absorbed and work done by the gas is 10 J and 18 J respectively. Now gas is brought back to state 'X' by another process during which 6 J of heat is evolved. In the reverse process of 'Y' to 'X',

18 J of the work is done by the gas 'A'.

2 J of the work is done by the gas 'A'.

12 J of the work is done on the gas 'A' by the surrounding.

14 J of the work is done on the gas 'A' by the surrounding.

Answer and worked solution

Official answer: D

X → Y. $\Delta U=q+w=10-18=-8$ J.

Y → X. $\Delta U=+8$ J and $q=-6$ J, so the work done on the gas is $w=\Delta U-q=8+6=14$ J.

(D)

Topics:First law and enthalpy

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JEE Main 2026 · 2 Apr · Shift 2, Chemistry question 54