JEE Main 2026 · 2 Apr · Shift 1 · Chemistry Q67 · Dronacharya Exams

My attemptsTake a paper

← JEE Main 2026 · 2 Apr · Shift 1

ChemistryList match+4 / -1Question 67 of 75

Match List - I with List - II.

Choose the correct answer from the options given below :

List - I: Mixture of Compounds

A
Diethyl amine + Ethyl amine
B
Acetaldehyde + Acetone
C
Ethanol + Phenol
D
Benzoic acid + Cinnamic acid

List - II: Reagent used to distinguish

I
Bromine water
II
$\ce{CHCl3}$ + KOH, Δ
III
Neutral $\ce{FeCl3}$
IV
Ammonical silver nitrate

A

A-IV, B-II, C-I, D-III

B

A-IV, B-II, C-III, D-I

C

A-II, B-IV, C-I, D-III

D

A-II, B-IV, C-III, D-I

Answer and worked solution

Official answer: D

A (2° vs 1° amine): carbylamine test, $\ce{CHCl3}$ /KOH, Δ, gives an isocyanide only with ethylamine. → II
B (aldehyde vs ketone): Tollens' reagent (ammoniacal $\ce{AgNO3}$ ) gives a silver mirror only with acetaldehyde. → IV
C (alcohol vs phenol): neutral $\ce{FeCl3}$ gives a violet colour with phenol. → III
D (benzoic vs cinnamic acid): bromine water is decolourised by the C=C of cinnamic acid. → I

Match: A-II, B-IV, C-III, D-I.

(D)

Topics:Detection of functional groups Amines

← Previous question Next question →