JEE Main 2026 · 2 Apr · Shift 1 · Chemistry Q66

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ChemistrySingle correct+4 / -1Question 66 of 75

For the given molecule, " $x$ ", the preferred site for the attack of the electrophile is :

x = benzanilide, C₆H₅-CO-NH-C₆H₅. On the benzoyl ring, p marks a position ortho and r a position meta to the carbonyl; on the N-phenyl ring, s marks a position ortho and u the position para to the NH.

Predominantly at "r"

"r" and "u"

"p" and "s"

Predominantly at "u"

Answer and worked solution

Official answer: D

Which ring is activated? In benzanilide, $\ce{Ph-CO-NH-Ph}$ , the NH lone pair (only partly drawn into the C=O) activates the N-phenyl ring and directs ortho/para. The benzoyl ring is deactivated by the carbonyl.

Position. On the N-phenyl ring the bulky $\ce{-NHCOPh}$ group hinders the ortho position (s), so attack occurs predominantly para, at "u".

(D)

Topics:Aromatic hydrocarbons and electrophilic substitution Amines

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JEE Main 2026 · 2 Apr · Shift 1, Chemistry question 66