JEE Main 2022 · 30 Jul · Shift 2 · Physics Q12

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PhysicsSingle correct+4 / -1Question 12 of 90

In an A.C circuit, V & I are given by V = 250 sin (100 t) volt and I = 10 sin $\left(100t+\dfrac\pi3\right)$ A respectively. The power dissipated in the circuit is:

2500 W

625 W

1250 W

625\sqrt2

Answer and worked solution

Official answer: B

Average power $\frac12V_0I_0\cos\phi=\frac12\times250\times10\times\frac12=625$ W.

(B)

Topics:Power in AC circuits

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JEE Main 2022 · 30 Jul · Shift 2, Physics question 12