JEE Main 2022 · 30 Jul · Shift 2 · Physics Q11 · Dronacharya Exams

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PhysicsSingle correct+4 / -1Question 11 of 90

The current I drawn out of the battery connected in the given circuit is:

A 9 V battery; across it a 3 Ω resistor, and in parallel a branch of 1.5 Ω in series with 6 Ω and 2 Ω, which are in parallel with each other.

A

5 A

B

6 A

C

7 A

D

8 A

Answer and worked solution

Official answer: B

Reduce. $6\parallel2=1.5$ Ω, plus 1.5 Ω gives 3 Ω, in parallel with the 3 Ω: 1.5 Ω.

Current $\frac9{1.5}=6$ A.

(B)

Topics:Series and parallel resistors

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