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← JEE Main 2022 · 30 Jul · Shift 2
MathematicsSingle correct+4 / -1Question 78 of 90

JEE Main 2022 · 30 Jul · Shift 2, Mathematics question 78

If the mean and median of the data

x 0 − 10 10 − 20 20 − 30 30 − 40 40 − 50
f 3 6 2 x y Σf = 20

are equal, then xy2xy^2 is equal to

Choose one option
Answer and worked solution

Official answer: A

Median. x+y=9x+y=9; the 10th value lies in 20-30: median =20+10−92×10=25=20+\frac{10-9}2\times10=25.

Mean 155+35x+45y20=25\frac{155+35x+45y}{20}=25 gives 7x+9y=697x+9y=69, so y=3y=3, x=6x=6 and xy2=54xy^2=54.

(A)