JEE Main 2022 · 30 Jul · Shift 2 · Chemistry Q39

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ChemistrySingle correct+4 / -1Question 39 of 90

The E° (volt) values are : Al $^{3+}$ /Al, −1.66, Sc $^{3+}$ /Sc, −2.08, Fe $^{3+}$ /Fe $^{2+}$ , +0.77, Hg $_2^{2+}$ /Hg, +0.79. Arrangement of cations, Al $^{3+}$ , Sc $^{3+}$ , Fe $^{3+}$ and Hg $_2^{2+}$ in decreasing order of oxidizing strength is

\mathrm{Al^{3+}>Sc^{3+}>Fe^{3+}>Hg_2^{2+}}

\mathrm{Hg_2^{2+}>Fe^{3+}>Sc^{3+}>Al^{3+}}

\mathrm{Hg_2^{2+}>Fe^{3+}>Al^{3+}>Sc^{3+}}

\mathrm{Sc^{3+}>Al^{3+}>Fe^{3+}>Hg_2^{2+}}

Answer and worked solution

Official answer: C

Oxidising strength follows E°: $\mathrm{Hg_2^{2+}}$ (+0.79) > $\mathrm{Fe^{3+}}$ (+0.77) > $\mathrm{Al^{3+}}$ (−1.66) > $\mathrm{Sc^{3+}}$ (−2.08).

(C)

Topics:Galvanic cells and EMF

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JEE Main 2022 · 30 Jul · Shift 2, Chemistry question 39