JEE Main 2022 · 30 Jul · Shift 2 · Chemistry Q38

ChemistrySingle correct+4 / -1Question 38 of 90

The correct option for relative covalent nature of compounds is

KF > KI

\mathrm{SnCl_4>SnCl_2}

KF > LiF

NaCl > HCl

Answer and worked solution

Official answer: B

Fajans' rules. Sn⁴⁺ is smaller and more highly charged than Sn²⁺, so it polarises Cl⁻ more: SnCl₄ is more covalent. The other pairs are reversed.

(B)

Topics:Ionic bonding

JEE Main 2022 · 30 Jul · Shift 2, Chemistry question 38