Skip to content
dronacharya.ai
← JEE Main 2022 · 29 Jul · Shift 2
PhysicsInteger+4 / -1Question 54 of 90

JEE Main 2022 · 29 Jul · Shift 2, Physics question 54

The velocity of a small ball of mass 0.3 g and density 8 g/cc when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is 1.3 g/cc, then the value of viscous force acting on the ball will be x×10−4x\times10^{-4} N. The value of xx is _______. [use g = 10 m/s2^2]

Answer and worked solution

Official answer: 25

Terminal velocity: viscous force = weight − buoyancy =mg(1−1.38)=3×10−3×0.8375≈25×10−4=mg\left(1-\frac{1.3}8\right)=3\times10^{-3}\times0.8375\approx25\times10^{-4} N.

Answer: 25

Topics:Terminal velocityBuoyancy and Archimedes' principle
← Previous questionNext question →