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← JEE Main 2022 · 29 Jul · Shift 2
PhysicsInteger+4 / -1Question 53 of 90

JEE Main 2022 · 29 Jul · Shift 2, Physics question 53

A metal wire of length 0.5 m and cross-sectional area 10−410^{-4} m2^2 has breaking stress 5×1085\times10^8 N m−2^{-2}. A block of 10 kg is attached at one end of the string and is rotating in a horizontal circle. The maximum linear velocity of block will be _______ m s−1^{-1}.

Answer and worked solution

Official answer: 50

Maximum tension 5×108×10−4=5×1045\times10^8\times10^{-4}=5\times10^4 N =mv2r=10v20.5=\dfrac{mv^2}r=\dfrac{10v^2}{0.5}, so v2=2500v^2=2500, v=50v=50 m/s.

Answer: 50