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← JEE Main 2022 · 29 Jul · Shift 2
PhysicsSingle correct+4 / -1Question 49 of 90

JEE Main 2022 · 29 Jul · Shift 2, Physics question 49

The root mean square speed of smoke particles of mass 5×10−175\times10^{-17} kg in their Brownian motion in air at NTP is approximately. [Given k = 1.38×10−231.38\times10^{-23} J K−1^{-1}]

Choose one option
Answer and worked solution

Official answer: C

rms speed 3kTm=3×1.38×10−23×2735×10−17≈0.015\sqrt{\dfrac{3kT}m}=\sqrt{\dfrac{3\times1.38\times10^{-23}\times273}{5\times10^{-17}}}\approx0.015 m/s = 15 mm/s.

(C)